n^2-n=1482

Solution for n^2-n=1482 equation:

n^2-n=1482

We move all terms to the left:

n^2-n-(1482)=0

We add all the numbers together, and all the variables

n^2-1n-1482=0

a = 1; b = -1; c = -1482;
Δ = b2-4ac
Δ = -12-4·1·(-1482)
Δ = 5929
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5929}=77$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-77}{2*1}=\frac{-76}{2}
=-38
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+77}{2*1}=\frac{78}{2}
=39
$